<?xml version="1.0" encoding="UTF-8"?><rss xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:atom="http://www.w3.org/2005/Atom" version="2.0"><channel><title><![CDATA[Topics tagged with non linear equations]]></title><description><![CDATA[A list of topics that have been tagged with non linear equations]]></description><link>https://community.secnto.com//tags/non linear equations</link><generator>RSS for Node</generator><lastBuildDate>Mon, 08 Jun 2026 23:24:15 GMT</lastBuildDate><atom:link href="https://community.secnto.com//tags/non linear equations.rss" rel="self" type="application/rss+xml"/><pubDate>Invalid Date</pubDate><ttl>60</ttl><item><title><![CDATA[MTH603 Download Handout]]></title><description><![CDATA[Download MTH603 Handout
]]></description><link>https://community.secnto.com//topic/2263/mth603-download-handout</link><guid isPermaLink="true">https://community.secnto.com//topic/2263/mth603-download-handout</guid><dc:creator><![CDATA[zaasmi]]></dc:creator><pubDate>Invalid Date</pubDate></item><item><title><![CDATA[Solution of Non Linear Equations (Bisection Method)]]></title><description><![CDATA[@oxama-malik said in Solution of Non Linear Equations (Bisection Method):

respected sir, sir ma na ye pochna tha ka regula falsi method ma hum ye bhi formula use kar sakta hai. please guide kar dya. the first approximation solution x1 is given by X1=(a(f(b))-b(f(a))/f(b)-f(a)

That is right. You can use this formula.
In fact, the formula given in the handouts becomes same after you simplify it. Also $x_{n-1}$ will become $a$ and $x_{n}$ will become $b$.
So use any from the two formulas you find easier.
Best wishes
]]></description><link>https://community.secnto.com//topic/2213/solution-of-non-linear-equations-bisection-method</link><guid isPermaLink="true">https://community.secnto.com//topic/2213/solution-of-non-linear-equations-bisection-method</guid><dc:creator><![CDATA[zaasmi]]></dc:creator><pubDate>Invalid Date</pubDate></item></channel></rss>